NO-LOAD EQUIVALENT CIRCUIT OF A TRANSFORMER - ELECTRICAL ENCYCLOPEDIA

NO-LOAD EQUIVALENT CIRCUIT OF A TRANSFORMER

What is a No-Load Transformer?

A transformer is said to be on no-load when its secondary winding is left open-circuited — meaning no load is connected across the output terminals. Under this condition, the secondary current I₂ = 0 and therefore the copper losses (I²R) in the secondary winding are zero.

During no-load operation, a small current called the no-load current (I₀) flows in the primary winding. This current is typically 3–5% of the rated full-load primary current. Since I₀ is very small, the primary copper losses (I₀²R₁) are negligible and can be ignored for practical analysis.

The no-load condition is important because it allows us to separate and measure the core losses (iron losses) of the transformer independently, which remain nearly constant from no-load to full-load.

Components of No-Load Current

The no-load current I₀ is not purely reactive — it has two components that serve distinct purposes:

Component Symbol Nature Function
Wattful (Active) Component Iw In phase with V₁ Supplies core loss (hysteresis + eddy current)
Wattless (Reactive) Component Lags V₁ by 90° Sets up mutual flux (Φm) in the core

The magnetizing component Iμ is much larger than the core-loss component Iw. This is why the no-load power factor (cos φ₀) of a transformer is very low — typically between 0.1 to 0.2 lagging.

I₀ = √(Iw² + Iμ²)
Iw = I₀ × cos φ₀
Iμ = I₀ × sin φ₀

No-Load Equivalent Circuit

Using the above understanding, we can draw the no-load equivalent circuit of a transformer. The circuit models the transformer's behaviour when only the primary is energized and the secondary is open.

no-load equivalent circuit of a transformer

No-Load Equivalent Circuit of a Transformer

Key observations from the circuit:

  • Primary impedance (R₁, X₁) is neglected — because I₀ is so small that the voltage drop across primary winding impedance is negligible. Hence V₁ ≈ E₁.
  • Secondary impedance is absent — because the secondary is open-circuited and I₂ = 0, so no current flows through secondary resistance or reactance.
  • R₀ (core-loss resistance) — a fictitious resistance placed in parallel that draws current Iw, representing the power consumed as hysteresis and eddy current losses.
  • X₀ (magnetizing reactance) — a fictitious reactance in parallel that draws the magnetizing current Iμ, responsible for establishing the mutual flux in the core.

The parallel combination of R₀ and X₀ is called the excitation branch or no-load branch of the transformer equivalent circuit. The part inside the dotted box in the diagram represents the ideal transformer with turns ratio N₁:N₂.

Circuit Parameters and Formulas

From the equivalent circuit, we can derive the following relationships:

R₀ = V₁ / Iw
X₀ = V₁ / Iμ
No-load power input: W₀ = V₁ × I₀ × cos φ₀ = V₁ × Iw
cos φ₀ = W₀ / (V₁ × I₀)

These parameters are determined experimentally using the open-circuit (no-load) test. In this test, rated voltage is applied to the primary with secondary open, and the wattmeter reading gives core loss directly.

Parameter Formula Determined From
Core-loss resistance R₀ V₁ / Iw Open-circuit test
Magnetizing reactance X₀ V₁ / Iμ Open-circuit test
No-load power factor W₀ / (V₁ × I₀) Open-circuit test
Core loss W₀ = V₁ × Iw Wattmeter reading (OC test)

Phasor Diagram at No-Load

The phasor diagram helps visualize the phase relationships between voltage, flux, and current components at no-load:

  • Applied voltage V₁ is taken as the reference phasor.
  • Mutual flux Φm lags V₁ by 90° (since E₁ = −dΦ/dt leads flux by 90°, and V₁ ≈ E₁).
  • Magnetizing current is in phase with Φm (it produces the flux), hence lags V₁ by 90°.
  • Core-loss current Iw is in phase with V₁ (it represents real power dissipation).
  • No-load current I₀ is the phasor sum of Iw and Iμ, lagging V₁ by angle φ₀.

For a detailed phasor diagram with graphical representation, refer to No-Load Transformer Phasor Diagram.

Numerical Example

Problem: A 230/110 V, 50 Hz single-phase transformer draws a no-load current of 2 A at a power factor of 0.15 lagging. Determine R₀, X₀, Iw, Iμ, and core loss.

Given: V₁ = 230 V, I₀ = 2 A, cos φ₀ = 0.15

Iw = I₀ × cos φ₀ = 2 × 0.15 = 0.3 A
Iμ = I₀ × sin φ₀ = 2 × 0.9887 = 1.977 A

R₀ = V₁ / Iw = 230 / 0.3 = 766.67 Ω
X₀ = V₁ / Iμ = 230 / 1.977 = 116.34 Ω

Core loss W₀ = V₁ × Iw = 230 × 0.3 = 69 W

Notice that X₀ is much smaller than R₀, confirming that the magnetizing current is the dominant component of no-load current.

Practical Significance

Understanding the no-load equivalent circuit is essential for:

  • Transformer design — selecting core material with low hysteresis and eddy current losses to minimize Iw.
  • Efficiency calculation — core losses (obtained from no-load test) remain constant at all loads and directly affect efficiency at light loads.
  • Parallel operation — matching excitation characteristics ensures proper load sharing between transformers.
  • Energy auditing — distribution transformers remain energized 24/7; high no-load losses mean continuous energy waste even when demand is zero.
  • Complete equivalent circuit — the no-load branch is combined with series impedances (from short-circuit test) to form the full transformer equivalent circuit used in power system analysis.

Frequently Asked Questions

1. Why is primary winding impedance neglected in the no-load equivalent circuit?

The no-load current I₀ is only 3–5% of rated current. The voltage drop across primary impedance (I₀Z₁) is therefore negligible compared to the applied voltage V₁, so we assume V₁ ≈ E₁ for simplicity.

2. What losses does the no-load current supply?

The no-load current supplies only the core losses (iron losses) — which include hysteresis loss and eddy current loss. Primary copper loss exists but is negligible due to the very small magnitude of I₀.

3. How are R₀ and X₀ determined experimentally?

They are determined from the open-circuit (no-load) test. Rated voltage is applied to the primary with secondary open. The wattmeter gives core loss (W₀), ammeter gives I₀, and voltmeter gives V₁. From these, cos φ₀, Iw, Iμ, R₀, and X₀ are calculated.

4. Why is the no-load power factor of a transformer very low?

Because the magnetizing component Iμ (reactive) is much larger than the core-loss component Iw (active). The transformer core requires significant reactive current to establish the magnetic flux, while the real power consumed (core loss) is relatively small.

5. Does the no-load equivalent circuit change with loading?

The excitation branch (R₀ and X₀ in parallel) remains the same under loaded conditions. However, when load is connected, the series impedances of primary and secondary windings are added to form the complete equivalent circuit. The no-load branch is simply one part of the full model.

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